This is about solving projectiles. Please help?
An auto moving too fast on a horizontal stretch of mountain road, sides off the road falling into deep snow 43.9 m below the road and 87.7 m beyond the edge of the road.
a. How long did the auto take to fall?
b. How fast was it going when it left road? (in m/s and km/h)
c. What was its acceleration 10 m below the edge of the road?
a) since the initial vertical speed was zero, we can calculate the time to fall from
dist = 1/2 gt^2
43.9 m = 1/2 (9.8 m/s/s) t^2
t=sqrt[2 x 43.9/9.8] = 3 s
b) assuming no frictional forces, the horizontal speed is constant, so if the car traveled 87.7 m before crashing in 3 s of travel, its horizontal speed on leaving the road was
speed = 87.7 m/3s = 29.3 m/s
c) the only force acting on the car is gravity, so the accel during free fall is always the accel of gravity, or 9.8 m/s/s toward the ground
'87 Ford F-250 on a mountain powerline road
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