PLEASE HELP ON THIS ALGEBRA 1-2 PROBLEM ON SYSTEMS AND EQUATIONS!!!?
please name all the variables and show steps and work because i really dont understand this problem. the problem is below.
A toy store has a number of bicycles, tricycles, and wagons in stock. IIf there are an equal number of tricycles and wagons, and a total of 60 pedal and 180 wheels, how many wagons, bicycles and tricycles are there.
THANK YOU IN ADVANCE! 
A system of equations can be confusing but there are steps to solving it. One thing to know is that you will need one equation for every variable you need to solve. So let makes some variables, b = bikes, t= trikes and w= wagons. Now we need to set up our equations.
So we know that each trike has three wheels a bike two and a wagon three so for the total number of wheels the equation is 3t+4w+2b = 180
Next there are an equal number of trikes and wagons so t=w. This means were ever we see a t or w we can replace with the other
Finally a trike and a bike each have two pedals each so 2t+2b = 60 now we have all the equations we need let's Solve!
Let's simplify our equations by replacing w with t since we know that t = w.
So: our new system looks like this: 3t+4t+2b= 180 now we can combine like terns 7t+2b=180
Next we have 2t+2b=60.
The next step we cancel out one of the variables to make the equation solvable. Let's make b disappear.
-1(2t+2b= 60)<-I'm multiplying this entire equation by negative one to make the b go away so we get: -2t-2b = -60 and now we cancel the b by combining it with the other equation and we get.
(7t+2b=180) + (-2t-2b=-60) we get 5t=120. Now divide by five to solve for t and we get t=24 we also know that t = w so the number of wagons is also 24. Now with that we can solve for be by placing t and w into our original equations.
2(24)+2b = 60. Solve again and we get b= to six.
So there are 24 trikes 24 wagons and 6 bikes!
60-second Bike Tips: PEDALLING
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