Who understands this strange tension problem?
A right triangular frame ABC, made of light struts, is freely pivoted at point C. Strut AB is maintained in a horizontal position by a horizontal rope between points A and D. Strut AC has a length a=0.5m and strut BC has length b=0.3m. A block of mass M=6 kg is suspended from a rope that is attached at point B and that passes over a frictionless pulley. The rope at B forms a 30 degree angle with the horizon, as shown. In fig. 11.2, the tension in the horizontal rope AD is closest to?
Fig:
Try to explain each step of the process.
What you drew does not appear as a "Right Triangle" it appears more equilateral. Is it a Right Triangle or not? If it is a right triangle which corner is the 90 degree angle?
I'm going to go with it is the classic 3-4-5 Right Triangle===>
Strut AC is the hypotenuse ===>
Angle B is the Right Angle ====>
If AB is horizontal then BC must be vertical
Now it is easy, we resolve the force on B into horizontal and vertical. We don't need to consider the vertical since BC is vertical it causes no Moment about C
F = MA
F = 6kg * 9.8 = 58.8 N That is a hypotenuse
cos 30 = Th/58.8
AD is the same tension
Pivot tutorial - 11 frame Run loop
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