Bumper Spring 11


Physics Help please!!!!?

Blocks (mass 5.50 ) and (mass 11.50 ) move on a frictionless, horizontal surface. Initially, block is at rest and block is moving toward it at 9.00 . The blocks are equipped with ideal spring bumpers. The collision is head-on, so all motion before and after the collision is along a straight line. Let be the direction of the initial motion of .

Find the maximum energy stored in the spring bumpers.

And the velocity of each block at that time.

Just need a little help with this one, its driving me crazy.
Can someone show me how to do this, thanks.

I can't tell which of your blocks is the one that is moving so I'll assume its the 5.5 kg one.

The trick is to realise that when the blocks are at their closest, they must both be moving with the same velocity - makes sense when you think about it.
And at closest approach the springs are most compressed and so have their maximum stored energy.

Since they both have the same velocity and since momentum is conserved.

Momentum before = 5.5 . 9 = Momentum at closest = (5.5 + 11.5) V

V = 49.5 / 17 = 2.91 m/s

That's the answer to the second question - both blocks have the same velocity of 2.91 m/s

The energy stored in the bumpers is the initial energy – the kinetic energy of the blocks at closest approach.

222.75 – 72.066 = 151 J

Now - did I chose the right block to be moving?

Production Bumper Spring 2007

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