Algebra question for everyone?
Solve the problem.
Karin biked at 13 mph for a time but got a flat tire. She then walked at 5 mph. She traveled a total of 93 miles. Had she biked the whole time, she would have gone 117 miles. How many hours did she walk?
Let x = time riding a bike at 13 mph
Let y = time walking at 5 mph
x + y = total time traveling (in hours)
(13 mph)(x) = distance traveled on a bike
(5 mph)(y) = distance traveled on foot
13x + 5y = 93 miles
on bike alone:
13 (x+y) = 117 miles
Subtract equation [2] from equation [1] to eliminate the variable x:
13x + 13y = 117 [1]
13x + 5y = 93 [2]
----------------------------
8y = 24
y = 3
since y is the time she spent walking, she walked for a total of 3 hours.
George Peck enters Fat Tire Bike Festival on a Unicycle 1993
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