Physics Friction Question. Person rides a bike and stops. Given: 50 km/Hr, 95kg, 0.36 friction?
Gina is riding her bicycle on a path when she comes around a corner and sees that a fallen tree is blocking the way 42 m ahead. If the coefficient of friction between her bicycle’s tires and the gravel path is 0.36, and she is traveling at 50 km/hr, how much stopping distance will she require (assume the only horizontal force acting on her is friction)? Gina and her bicycle, together, have a mass of 95 kg.
I am still confused with that.
The answer is 27.3.
But i don't know what i need to do.
F=ma. solve for acceleration or deceleration. a = F/m = .36/95 = -.00379m/s^2. that's not a lot.
a is negative because it is supposed to slow the bicycle down.
there are a few equations that you could try that deal with acceleration, i think the best would be V^2=Vo^2 -2ax which is final velocity squared equals initial velocity minus 2ax. for her to stop, the final velocity should be zero. the initial velocity is still 50. solve for x.
I didn't check the numbers, but i'm guessing she is going to need her brakes.
Suwanee Creek Bikes Thursday Ride, May 20, 2010
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